25i^2-40i+16=0

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Solution for 25i^2-40i+16=0 equation:


Simplifying
25i2 + -40i + 16 = 0

Reorder the terms:
16 + -40i + 25i2 = 0

Solving
16 + -40i + 25i2 = 0

Solving for variable 'i'.

Factor a trinomial.
(4 + -5i)(4 + -5i) = 0

Subproblem 1

Set the factor '(4 + -5i)' equal to zero and attempt to solve: Simplifying 4 + -5i = 0 Solving 4 + -5i = 0 Move all terms containing i to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -5i = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -5i = 0 + -4 -5i = 0 + -4 Combine like terms: 0 + -4 = -4 -5i = -4 Divide each side by '-5'. i = 0.8 Simplifying i = 0.8

Subproblem 2

Set the factor '(4 + -5i)' equal to zero and attempt to solve: Simplifying 4 + -5i = 0 Solving 4 + -5i = 0 Move all terms containing i to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -5i = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -5i = 0 + -4 -5i = 0 + -4 Combine like terms: 0 + -4 = -4 -5i = -4 Divide each side by '-5'. i = 0.8 Simplifying i = 0.8

Solution

i = {0.8, 0.8}

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